7.6^2+b^2=9.2^2

Solution for 7.6^2+b^2=9.2^2 equation:

7.6^2+b^2=9.2^2

We move all terms to the left:

7.6^2+b^2-(9.2^2)=0

We add all the numbers together, and all the variables

b^2-26.88=0

a = 1; b = 0; c = -26.88;
Δ = b2-4ac
Δ = 02-4·1·(-26.88)
Δ = 107.52
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{107.52}}{2*1}=\frac{0-\sqrt{107.52}}{2}
=-\frac{\sqrt{}}{2}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{107.52}}{2*1}=\frac{0+\sqrt{107.52}}{2}
=\frac{\sqrt{}}{2}
$